2u^2+3u=5

Solution for 2u^2+3u=5 equation:

Simplifying
2u2 + 3u = 5

Reorder the terms:
3u + 2u2 = 5

Solving
3u + 2u2 = 5

Solving for variable 'u'.

Reorder the terms:
-5 + 3u + 2u2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 3u + 2u2 = 0

Factor a trinomial.
(-5 + -2u)(1 + -1u) = 0

Subproblem 1
Set the factor '(-5 + -2u)' equal to zero and attempt to solve:

Simplifying
-5 + -2u = 0

Solving
-5 + -2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -2u = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -2u = 0 + 5
-2u = 0 + 5

Combine like terms: 0 + 5 = 5
-2u = 5

Divide each side by '-2'.
u = -2.5

Simplifying
u = -2.5
Subproblem 2
Set the factor '(1 + -1u)' equal to zero and attempt to solve:

Simplifying
1 + -1u = 0

Solving
1 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1u = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1u = 0 + -1
-1u = 0 + -1

Combine like terms: 0 + -1 = -1
-1u = -1

Divide each side by '-1'.
u = 1

Simplifying
u = 1
Solution
u = {-2.5, 1}